 ... an angle with the tangent equal to that made by the tangent with the axis. Cor. 3. Now as V bisects TD and VB is, parallel to PD, the point .B bisects' TP. Draw FB, and that line bisects the base of an isosceles triangle, it is therefore perpendicular...  New Series of The Mathematical Repository - الصفحة 62بواسطة Thomas Leybourn - 1814عرض كامل - لمحة عن هذا الكتاب
 | Albert Ensign Church - 1859 - عدد الصفحات: 360
...isosceles triangle, it is therefore perpendicular to that base. Hence, we have this general truth, / If from, the focus of a parabola a perpendicular be drawn to any tangent, it will meet the tangent on the axis of Y. Also, from the two similar right angled triangles, we have... | |
 | Horatio Nelson Robinson - 1862 - عدد الصفحات: 356
...isosceles triangle, it is therefore perpendicular to the base. Hence, we have this general truth : If from the focus of a parabola a perpendicular be drawn to any tangent to the curve, it will meet the tangent on the axis of Y. Also, from the two similar right-angled triangles, FB V... | |
 | Horatio Nelson Robinson - 1863 - عدد الصفحات: 362
...isosceles triangle, it is therefore perpendicular to the base. Hence, we have this general truth : If from the focus of a parabola a perpendicular be drawn to any tangent to the curve, it will meet the tangent on the axis of Y. Also, from the two similar right-angled triangles, FB V... | |
 | E. J. Brooksmith - 1889 - عدد الصفحات: 356
...obtained for about four-fifths of this paper.] [Great importance is attached to accuracy.] l. Show that, if from the focus of a parabola a perpendicular be drawn to any tangent, the point of intersection lies on the tangent at the vertex. Having given the extremities of a focal... | |
| |
