The Elements of Mechanics, Comprehending Statics and Dynamics: With a Copious Collection of Mechanical Problems. Intended for the Use of Mathematical Students in Schools and Universities ...1848 - 258 من الصفحات |
المحتوى
| 121 | |
| 122 | |
| 125 | |
| 127 | |
| 128 | |
| 129 | |
| 131 | |
| 132 | |
| 70 | |
| 76 | |
| 82 | |
| 88 | |
| 93 | |
| 97 | |
| 100 | |
| 101 | |
| 103 | |
| 104 | |
| 106 | |
| 107 | |
| 108 | |
| 111 | |
| 114 | |
| 115 | |
| 117 | |
| 118 | |
| 119 | |
| 120 | |
| 135 | |
| 136 | |
| 138 | |
| 140 | |
| 146 | |
| 152 | |
| 158 | |
| 164 | |
| 168 | |
| 174 | |
| 177 | |
| 183 | |
| 190 | |
| 196 | |
| 202 | |
| 215 | |
| 223 | |
| 230 | |
| 250 | |
طبعات أخرى - عرض جميع المقتطفات
عبارات ومصطلحات مألوفة
acceleration accelerative force angle angular velocity applied axes axle beam Calc called centre of gravity centrifugal force circumference co-ordinates components concurring forces consequently consider constant cord curve cycloid cylinder determine the centre differential direction distance dt dt dx dy equa equal equilibrating equilibrium expression feet fixed point forces acting foregoing hence horizontal plane impulse inclined plane inertia integral intensity length lever mass moment of inertia multiplied obviously parallel forces particle pass pendulum perpendicular plane of xy point of application position pressure principal axes PROBLEM projection pulley quantities radius radius of gyration rectangular rection represent resistance respect rest resultant revolve rotation side space strain string substituting suppose surface tangent tendency tension theory tion triangle vary vertical direction vertical plane wheel whole
مقاطع مشهورة
الصفحة 171 - The third law teaches that, in the motion of the planets, the squares of the times of revolution are as the cubes of the mean distances from the sun...
الصفحة 115 - ... the weight W, then this would be double of that which would be necessary to produce the fracture in the common case : for, dividing the weight W into four equal parts, we may conceive two of these parts employed in producing the strain or fracture at E, and one of each of the other parts as acting in / opposition to w and w, and by these means tending to produce the fractures at F and F.
الصفحة 189 - The moment of inertia of a plane area with respect to an axis perpendicular to the plane of the...
الصفحة 30 - Yes, or a bit of poetry even. The first thing that occurs." Edith said: And yet no force, however great, Can stretch a cord, however fine, Into a horizontal line That shall be absolutely straight.
الصفحة 45 - ... rest on a plane curve by the action of any number of forces in the plane of the curve, the resultant must obviously be in the direction of the normal to the curve at that point, and equivalent to the pressure the curve sustains. For, if the resultant had any other direction, it might be resolved into two, one in the direction of the normal, and the other in the direction of the tangent to the curve ; the former would be opposed by the reaction of the curve ; the latter, being unopposed, would...
الصفحة 164 - COR. The time t being independent of the abscissa h, will be the same, from whatever point in the curve the body begins to descend ; in this respect differing from the motion in circular arcs. On account of this remarkable property the cycloid is called tautochronal. 359. SCHOL. The property of tautochronism which attaches to the cycloid was supposed to give peculiar advantages to a pendulum made to oscillate in this curve. The...
الصفحة 190 - No additional theory is needed to find the moment of inertia of a solid of revolution with respect to its axis, but other solids are out of reach at present (§ 235).
الصفحة 82 - The moment of the resultant of several forces applied to a point is equal to the sum of the moments of the components.
الصفحة 191 - ... body there will be different radii of gyration. Of all axes taken in the same body parallel to each other, that which passes through the centre of gravity has the least radius of gyration. If the radius of gyration of any axis passing through the centre of gravity be given, that of any parallel axis can be found; for the square of the radius of gyration of any axis is equal to the square of the distance of that axis from the centre of gravity added to...
الصفحة 63 - dx ^/Zrx— x* ' \ dx* \/2rx — x* xdx so that the distance of the centre of gravity from the centre of the circle is a fourth, proportional to the arc, the radius, and the chord of the arc.