...feet wide instead of 27 feet. How much additional area does it contain f 2. Area of a Parallelogram. The area of a parallelogram is equal to the product of its base and altitude. The base is any one of the sides. The altitude is the perpendicular distance between the base and the...

...the product of 6 and 5, the numbers which express the lengths of the sides. PROP. IV. THEOREM. 309. The area of a parallelogram is equal to the product of its base and altitude. BFC A b D Given O ABCD, with its altitude DF=a, and its base To Prove area ABCD = ax b. Proof. Draw...

...Corollary. The area of a rectangle is equal to the product of its base and its altitude. THEOREM IV. The area of a parallelogram is equal to the product of its base and its altitude. THEOREM V. The area of a triangle is equal to half the product of its base and its altitude....

...evident by dividing the figure into squares, each BOOK IV. PLANE GEOMETKY". PROPOSITION IV. THEOREM. 400. The area of a parallelogram is equal to the product of its base by its altitude. BE CF CE A b ~ DA J> ' D Let AEFD be a parallelogram, b its base, and a its altitude....

...drawn, the tangent is the mean proportional between the whole secant and its external segment. 400. The area of a parallelogram is equal to the product of its base by its altitude. 401. Parallelograms having equal bases and equal altitudes are equivalent. 403....

...assumed without proof. Among the other error» in proving the second part it wa.s taken for true that the area of a parallelogram is equal to the product of its two adjacent sides. Questions 7. 8, and 9 were correctly demonstrated by nearly all (a considerable...

...=0= A AD F + A BED ; that is, ABCD =0= ABEF. Therefore, etc. QED MILNE'S GEOM. — 12 332. Cor. I. The area of a parallelogram is equal to the product of its base by its altitude. 333. Cor. II. Parallelograms are to each other as the products of their bases...

...by dividing the figure into squares, each T~ BOOK IV. PLANE GEOMETRY. PROPOSITION IV. THEOREM. 400. The area of a parallelogram is equal to the product of its base by its altitude. BE OF B GE A b DAI) D Let AEFD be a parallelogram, b its base, and a its altitude....

...units) in the rectangle is 4 x 3 or 12. The area then is 12 square feet. 588. COROLLARY. The area of any parallelogram is equal to the product of its base and altitude. Let ABCD be any parallelogram f BEC and DE be its altitude. To Prove ABCD = AD x DE. Proof. Draw AF _L to AD, meeting BC prolonged...

...inches; that is, a figure 2 inches square, and its area is 4 square inches. 25. Area of a Parallelogram. The area of a parallelogram is equal to the product of its base and altitude. Let AB CD, Fig. 4, be any parallelogram. Draw A Fand BE perpendicular to the two opposite sides AB and...