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" The surface of a sphere is equal to the product of its diameter by the circumference of a great circle. "
Elements of Geometry and Trigonometry - الصفحة 215
بواسطة Adrien Marie Legendre - 1852 - عدد الصفحات: 432
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Elements of Geometry and Trigonometry: With Applications in Mensuration

Charles Davies - 1864 - عدد الصفحات: 358
...THEOREM XXIII. The surface of a sphere is equal to ihr product of its diameter by the ctrcumference of a great circle. Let ABCDE be a semicircle. Inscribe in it any regular semi-polygon, and from the centre O draw OF perpendicular to one of the sides. I,et the...

Elements of Geometry and Trigonometry

C. Davies - 1867 - عدد الصفحات: 342
...by ED+DC, is equal to (HI+IP)x circumference ON, or equal to -/IP x circumference ONTHEOREM XXIIIThe surface of a sphere is equal to the product of its diameter by the circumference of a great circleLet ABCDE be a semicircle- Inscribe in it any regular semi-polygon, and from the centre O draw...

Elements of Geometry: With Practical Applications to Mensuration

Benjamin Greenleaf - 1868 - عدد الصفحات: 340
...the circ. 0I, or to the product of the axis AF by the circ. 0 I. PKO POSITION VIII. — THEOREM. 588. The surface of a sphere is equal to the product of...diameter by the circumference of a great circle. Let ABCDEP be a semicircle in which is inscribed any regular semi-polygon ; from the centre, 0, draw 01...

Elements of Geometry and Trigonometry: With Practical Applications

Benjamin Greenleaf - 1869 - عدد الصفحات: 516
...the circ. 0 1, or to the product of the axis AF by the circ. 0 1. PROPOSITION VIII. — THEOREM. 588. The surface of a sphere is equal to the product of...diameter by the circumference of a great circle. Let ABCDEF be a semicircle in which is inscribed any regular semi-polygon ; from the centre, 0, draw 0...

Elements of Geometry and Trigonometry: With Applications in Mensuration

Charles Davies - 1870 - عدد الصفحات: 392
...by ED+DC, is equal to (HI+IP)x circumference ON, or equal to HPx. circumference ON. THEOREM XXIII. The surface of a sphere is equal to the product of...circle. Let ABCDE be a semicircle. Inscribe in it any regular semi-polygon, and from the centre О draw OF perpendicular to one of the sides. Let the...

A Treatise on Elementary Geometry: With Appendices Containing a Collection ...

William Chauvenet - 1871 - عدد الصفحات: 380
...radius is the chord of the generating arc of the zone. ,i_ PROPOSITION XI.— THEOREM. 41. The area of the surface of a sphere is equal to the product of...its diameter by the circumference of a great circle. This follows directly from the preceding proposition, since the surface of the whole sphere may be...

Elements of Geometry, Conic Sections, and Plane Trigonometry

Elias Loomis - 1871 - عدد الصفحات: 302
...base of the frustum, its upper base, and a mean proportional between them. PROPOSITION VII. THEOREM. The surface of a sphere is equal to the product of its diaiiw ter by the circumference of a great circle. Let ABDF be the semicircle by the revolution of...

An Elementary Geometry

William Frothingham Bradbury - 1872 - عدد الصفحات: 124
...passes through the centre of the sphere, its radius will be the radius of the sphere. THEOREM XV. 61 . The surface of a sphere is equal to the product of...by the circumference of a great circle. Let ABCDE F be the semicircle by whose revolution about the diameter AF, the sphere may be described ; then the...

An Elementary Geometry and Trigonometry

William Frothingham Bradbury - 1872 - عدد الصفحات: 262
...great circle. A section made by a plane not passing through the centre is called a small circle. 61 i The surface of a sphere is equal to the product of...diameter by the circumference of a great circle. Let ABC DEF be the semicircle by whose revolution about the diameter AF, the sphere may be described; then...

A Treatise on Elementary Geometry: With Appendices Containing a Collection ...

William Chauvenet - 1872 - عدد الصفحات: 382
...radius is the chord of the generating arc of the zone. B PROPOSITION XI— THEOREM. 41. The area of the surface of a sphere is equal to the product of...its diameter by the circumference of a great circle. This follows directly from the preceding proposition, since the surface of the whole sphere may be...




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